Defanging an ip address

class Solution:
    def defangIPaddr(self, address: str) -> str:
        res = ""
        for i in address:
            if i == ".":
                res += "[.]"
            else:
                res += i

        return res

Defanging an IP Address

Difficulty: Easy

Given a valid (IPv4) IP address, return a defanged version of that IP address.

A defanged IP address replaces every period "." with "[.]".

 

Example 1:

Input: address = "1.1.1.1"
Output: "1[.]1[.]1[.]1"

Example 2:

Input: address = "255.100.50.0"
Output: "255[.]100[.]50[.]0"

 

Constraints:

  • The given address is a valid IPv4 address.