N th tribonacci number

class Solution:
    def tribonacci(self, n: int) -> int:
        if n == 0:
            return 0
        if n == 1:
            return 1
        if n == 2:
            return 1
        dp = [0] * (n + 1)
        dp[0] = 0
        dp[1] = 1
        dp[2] = 1
        for i in range(3, n + 1):
            dp[i] = dp[i - 3] + dp[i - 2] + dp[i - 1] 
        # print(dp)
        return dp[n]

N-th Tribonacci Number

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The Tribonacci sequence T_n is defined as follows: 

T₀ = 0, T₁ = 1, T₂ = 1, and T_n+3 = T_n + T_n+1 + T_n+2 for n >= 0.

Given n, return the value of T_n.

 

Example 1:

Input: n = 4
Output: 4
Explanation:
T_3 = 0 + 1 + 1 = 2
T_4 = 1 + 1 + 2 = 4

Example 2:

Input: n = 25
Output: 1389537

 

Constraints:

• 0 <= n <= 37
• The answer is guaranteed to fit within a 32-bit integer, ie. answer <= 2^31 - 1.