Valid parentheses

class Solution:
    def isValid(self, s: str) -> bool:
        stack = []
        for i in s:
            if i == '(':
                stack.append(')')
            elif i == '[':
                stack.append(']')
            elif i == '{':
                stack.append('}')
            else:
                if not stack or i != stack.pop():
                    return False
        if len(stack) != 0:
            return False
        return True

Valid Parentheses

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Given a string s containing just the characters '(', ')', '{', '}', '[' and ']', determine if the input string is valid.

An input string is valid if:

1. Open brackets must be closed by the same type of brackets.
2. Open brackets must be closed in the correct order.
3. Every close bracket has a corresponding open bracket of the same type.

 

Example 1:

Input: s = "()"
Output: true

Example 2:

Input: s = "()[]{}"
Output: true

Example 3:

Input: s = "(]"
Output: false

 

Constraints:

• 1 <= s.length <= 104
• s consists of parentheses only '()[]{}'.