Integer break

class Solution:
    def integerBreak(self, n: int) -> int:
        dp = [0] * (n + 1)
        dp[2] = 1
        for i in range(3, n + 1):
            for j in range(1, i):
                dp[i] = max(
                    dp[i],
                    j * (i - j),
                    j * dp[i - j]
                )
        # print(dp)
        return dp[n]

Integer Break

---

Given an integer n, break it into the sum of k positive integers, where k >= 2, and maximize the product of those integers.

Return the maximum product you can get.

 

Example 1:

Input: n = 2
Output: 1
Explanation: 2 = 1 + 1, 1 × 1 = 1.

Example 2:

Input: n = 10
Output: 36
Explanation: 10 = 3 + 3 + 4, 3 × 3 × 4 = 36.

 

Constraints:

• 2 <= n <= 58