Ransom note

class Solution:
    def canConstruct(self, ransomNote: str, magazine: str) -> bool:
        count = [0] * 26
        for i in magazine:
            count[ord(i) - ord('a')] += 1
        for i in ransomNote:
            count[ord(i) - ord('a')] -= 1
            if count[ord(i) - ord('a')] < 0:
                return False
        return True

Ransom Note

Difficulty: Easy

Given two strings ransomNote and magazine, return true if ransomNote can be constructed by using the letters from magazine and false otherwise.

Each letter in magazine can only be used once in ransomNote.

 

Example 1:

Input: ransomNote = "a", magazine = "b"
Output: false

Example 2:

Input: ransomNote = "aa", magazine = "ab"
Output: false

Example 3:

Input: ransomNote = "aa", magazine = "aab"
Output: true

 

Constraints:

  • 1 <= ransomNote.length, magazine.length <= 105
  • ransomNote and magazine consist of lowercase English letters.