Wildcard matching

class Solution:
    def isMatch(self, s: str, p: str) -> bool:
        m, n = len(s), len(p)
        dp = [[False] * (n + 1) for _ in range(m + 1)]
        dp[0][0] = True
        for i in range(1, n + 1):
            if p[i - 1] == "*":
                dp[0][i] = True
            else:
                break

        for i in range(1, m + 1):
            for j in range(1, n + 1):
                if p[j - 1] == '*':
                    dp[i][j] = dp[i - 1][j] or dp[i][j - 1]
                if p[j - 1] == '?' or s[i - 1] == p[j - 1]:
                    dp[i][j] = dp[i - 1][j - 1]

        return dp[m][n]

Wildcard Matching

Difficulty: Hard

Given an input string (s) and a pattern (p), implement wildcard pattern matching with support for '?' and '*' where:

  • '?' Matches any single character.
  • '*' Matches any sequence of characters (including the empty sequence).

The matching should cover the entire input string (not partial).

 

Example 1:

Input: s = "aa", p = "a"
Output: false
Explanation: "a" does not match the entire string "aa".

Example 2:

Input: s = "aa", p = "*"
Output: true
Explanation: '*' matches any sequence.

Example 3:

Input: s = "cb", p = "?a"
Output: false
Explanation: '?' matches 'c', but the second letter is 'a', which does not match 'b'.

 

Constraints:

  • 0 <= s.length, p.length <= 2000
  • s contains only lowercase English letters.
  • p contains only lowercase English letters, '?' or '*'.