Delete node in a bst
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, val=0, left=None, right=None):
# self.val = val
# self.left = left
# self.right = right
class Solution:
def deleteNode(self, root: Optional[TreeNode], key: int) -> Optional[TreeNode]:
if not root:
return root
if root.val == key:
if root.left and root.right:
curr = root.right
while curr.left:
curr = curr.left
curr.left = root.left
return root.right
if not root.left and root.right:
return root.right
if not root.right and root.left:
return root.left
if not root.left and not root.right:
return None
# if root.val > key:
root.left = self.deleteNode(root.left, key)
# if root.val < key:
root.right = self.deleteNode(root.right, key)
return root
Delete Node in a BST
Given a root node reference of a BST and a key, delete the node with the given key in the BST. Return the root node reference (possibly updated) of the BST.
Basically, the deletion can be divided into two stages:
- Search for a node to remove.
- If the node is found, delete the node.
Example 1:

Input: root = [5,3,6,2,4,null,7], key = 3 Output: [5,4,6,2,null,null,7] Explanation: Given key to delete is 3. So we find the node with value 3 and delete it. One valid answer is [5,4,6,2,null,null,7], shown in the above BST. Please notice that another valid answer is [5,2,6,null,4,null,7] and it's also accepted.![]()
Example 2:
Input: root = [5,3,6,2,4,null,7], key = 0 Output: [5,3,6,2,4,null,7] Explanation: The tree does not contain a node with value = 0.
Example 3:
Input: root = [], key = 0 Output: []
Constraints:
- The number of nodes in the tree is in the range
[0, 104]. -105 <= Node.val <= 105- Each node has a unique value.
rootis a valid binary search tree.-105 <= key <= 105
Follow up: Could you solve it with time complexity O(height of tree)?