N queens
class Solution:
def solveNQueens(self, n: int) -> List[List[str]]:
res = []
grid = [['.'] * n for i in range(n)]
def check(grid, row, col):
for i in range(row - 1, -1, -1):
if grid[i][col] == "Q":
return False
count = 1
for i in range(row - 1, -1, -1):
leftcol = col - count
rightcol = col + count
if leftcol >= 0 and grid[i][leftcol] == "Q":
return False
if rightcol < n and grid[i][rightcol] == "Q":
return False
count += 1
return True
def backtrack(grid, row):
# print(grid)
if row == n:
res.append(["".join(i) for i in grid])
return
for col in range(n):
grid[row][col] = 'Q'
if check(grid, row, col):
backtrack(grid, row + 1)
grid[row][col] = '.'
backtrack(grid, 0)
return res
N-Queens
The n-queens puzzle is the problem of placing n queens on an n x n chessboard such that no two queens attack each other.
Given an integer n, return all distinct solutions to the n-queens puzzle. You may return the answer in any order.
Each solution contains a distinct board configuration of the n-queens' placement, where 'Q' and '.' both indicate a queen and an empty space, respectively.
Example 1:

Input: n = 4 Output: [[".Q..","...Q","Q...","..Q."],["..Q.","Q...","...Q",".Q.."]] Explanation: There exist two distinct solutions to the 4-queens puzzle as shown above
Example 2:
Input: n = 1 Output: [["Q"]]
Constraints:
1 <= n <= 9