Minimum depth of binary tree

# Definition for a binary tree node.
# class TreeNode:
#     def __init__(self, val=0, left=None, right=None):
#         self.val = val
#         self.left = left
#         self.right = right
class Solution:
    def minDepth(self, root: Optional[TreeNode]) -> int:
        if not root:
            return 0

        queue = deque([(root, 1)])
        rs = 0
        node = root
        while node:
            node, node.level = queue.popleft()
            rs = node.level
            if not node.left and not node.right:
                return rs
            if node.left:
                queue.append((node.left, node.level + 1))
            if node.right:
                queue.append((node.right, node.level + 1))

Minimum Depth of Binary Tree

Difficulty: Easy


Given a binary tree, find its minimum depth.

The minimum depth is the number of nodes along the shortest path from the root node down to the nearest leaf node.

Note: A leaf is a node with no children.

 

Example 1:

Input: root = [3,9,20,null,null,15,7]
Output: 2

Example 2:

Input: root = [2,null,3,null,4,null,5,null,6]
Output: 5

 

Constraints:

  • The number of nodes in the tree is in the range [0, 105].
  • -1000 <= Node.val <= 1000